4(1/x-2)^2-(7/x-2)-2=0

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Solution for 4(1/x-2)^2-(7/x-2)-2=0 equation: 



4(1/x-2)^2-(7/x-2)-2=0



Domain of the equation: x-2)^2!=0

x∈R





Domain of the equation: x-2)!=0

x∈R



We get rid of parentheses

4(1/x-2)^2-7/x+2-2=0

We calculate fractions


(4(1*x)/(x-2)^2*x)+(-7x)/(x-2)^2*x)+2-2=0



We calculate terms in parentheses: +(4(1*x)/(x-2)^2*x), so:

4(1*x)/(x-2)^2*x

We add all the numbers together, and all the variables

4(+x)/(x-2)^2*x

We multiply all the terms by the denominator


4(+x)

We multiply parentheses

4x

Back to the equation:

+(4x)



We multiply all the terms by the denominator


4x*(x-2)^2*x)+2-2+(-7x)=0

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